a rectangular field is 49 my long and 35 my wide it has an inside cobbled path 1 metre along its side calculating the area of path
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Answered by
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Heya.
SAME QUESTION :- https://brainly.in/question/2090822
Your answer is here.
It is given that the length of field is 49 m and breadth of field is 35 m.
It is also given that there is a road from all sides of the field.
So, (in the attachment) you can see that length of field will become 49-2 = 47 m. (bcoz the road takes 1 m from both sides).
Same in the case of breadth, breadth of inner rectangle = 35 - 2 = 33 m.
(YOU CAN UNDERSTAND BETTER WITH THE HELP OF PICTURE)
Now, area of ABCD = 49 X 35 = 1715
Area of PQRS = 47 X 33 = 1551.
Now, area of road = ar (ABCD) - ar (PQRS)
= 1715 - 1551
= 164 m².
Hence, the area of road = 164 m².
Hope it helps
SAME QUESTION :- https://brainly.in/question/2090822
Your answer is here.
It is given that the length of field is 49 m and breadth of field is 35 m.
It is also given that there is a road from all sides of the field.
So, (in the attachment) you can see that length of field will become 49-2 = 47 m. (bcoz the road takes 1 m from both sides).
Same in the case of breadth, breadth of inner rectangle = 35 - 2 = 33 m.
(YOU CAN UNDERSTAND BETTER WITH THE HELP OF PICTURE)
Now, area of ABCD = 49 X 35 = 1715
Area of PQRS = 47 X 33 = 1551.
Now, area of road = ar (ABCD) - ar (PQRS)
= 1715 - 1551
= 164 m².
Hence, the area of road = 164 m².
Hope it helps
Attachments:
RehanAhmadXLX:
thanks
Answered by
3
Hey there!
KINDLY SEE THE ATTACHMENT PIC. ABOVE
Length of Outer Field, L = 49 m
Length of Inner Field, l = 49 - 2 m = 47 m (1m path for road is subtracted from both sides)
Breadth of Outer field, B = 35 m
Breadth of Inner field, b = 35 - 2 m = 33m (1m path for road is subtracted from both sides)
AREA OF PATH = ar (ABCD) - ar (MNOP)
= L × B - l × b
= 49 X 35 - 47 X 33
= 1715 - 1551 m²
= 164 m²
Hence,
Area of the path is = 164 m²
HOPE IT HELPED ^_^
KINDLY SEE THE ATTACHMENT PIC. ABOVE
Length of Outer Field, L = 49 m
Length of Inner Field, l = 49 - 2 m = 47 m (1m path for road is subtracted from both sides)
Breadth of Outer field, B = 35 m
Breadth of Inner field, b = 35 - 2 m = 33m (1m path for road is subtracted from both sides)
AREA OF PATH = ar (ABCD) - ar (MNOP)
= L × B - l × b
= 49 X 35 - 47 X 33
= 1715 - 1551 m²
= 164 m²
Hence,
Area of the path is = 164 m²
HOPE IT HELPED ^_^
Attachments:
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