Question

A rectangular field is 50 m by 40 m. It has two
roads through its centre ruming, parallel to its
side. The width of the longer and the shorter roads are 2 m and 2.5 m respectively . find the area of the roads and the area of the remaining portion of the field ? ​

Answer 1

Answer:

Let ABCD be the rectangular field and KLMN and PQRS the two rectangular roads with width 1.8 m and 2.5 m, respectively. Given that length of rectangular field = 50 m Breadth of rectangular field = 40m Area of rectangular field ABCD = 50 m x 40 m = 2000 m2 Area of the road KLMN = 40 m x 2.5 m = 100 m2 Area of the road PQRS = 50 m x 1.8 m = 90 m2 Clearly area of EFGH is common to the two roads. Thus, Area of EFGH = 2.5 m x 1.8 m = 4.5 m2 Hence, Area of the roads = Area of KLMN + Area of PQRS – Area of EFGH = (100 m2 + 90 m2) – 4.5 m2 = 185.5 m2 Area of the remaining portion of the field = Area of the rectangular field ABCD – Area of the roads = (2000 – 185.5) m2 = 1814.5 m2Read more on Sarthaks.com - https://www.sarthaks.com/690363/rectangular-field-50-by-40-it-has-two-roads-through-its-center-running-parallel-to-its-sides

Answer 2

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