Question

A rectangular field is 50 m long and 30 m wide. It consists of two perpendicular roads running through its centre and parallel to the length and breadth. The widths of the longer and shorter roads are 5m and 10 m respectively.

Find the cost of paving the roads at the rate of $150 per m2

Answer 1

Answer:

Mark me brainlist answer

Step-by-step explanation:

:

The “area of the longer road” =50 \times 2=100 m^{2}=50×2=100m

2

The “area of the shorter road” =40 \times 2.5=100 m^{2}=40×2.5=100m

2

“Total area of the rectangular field” =2 \times 2.5=5 \mathrm{m}^{2}=2×2.5=5m

2

“Area common” to both the roads =2 \times 2.5=5 \mathrm{m}^{2}=2×2.5=5m

2

“Total Area of the roads” =100+100-5=195 \mathrm{m}^{2}=100+100−5=195m

2

“Area of the remaining portion” of the field =2000-195=1805 \mathrm{m}^{2}=2000−195=1805m

2

Answer 2

Answer:

$7500

Step-by-step explanation:

pavement area = 5*10 =50m2

rate per m2= $150

50*150 = $7500