Question

a rectangular field is 50m by 40 m mahesh goes ten times round it how much distance does he cover?

Answer 1

perimeter of rectangle =2(l+b)
=2(50+40)
=2(90)
=180
Mahesh goes ten times round it
so the distance covered by mahesh=10×180=1800m

Answer 2

Final answer: Mahesh cover 1800 m distance when he goes ten times around the rectangular field of dimensions 50 m × 40 m.    

Given that: We are given,  and Mahesh goes ten times around  a rectangular field dimensions 50 m × 40 m.

To find: We have to find how much distance does Mahesh cover.

Explanation:

• Shape of the given filed = Rectangle

• Dimensions of the given rectangular field = 50 m × 40 m

So, length of the given rectangular field = 50 m

Breadth of the given rectangular field = 40 m

• First we have to calculate the perimeter of the rectangular field.

$Perimeter of rectangle = 2(length + breadth)$

$Perimeter of the rectangular field = 2(length of the field + breadth of the field)$

                                                     $=2$ × $(50+40)$

                                                     = $2$ × $90=180$ m

• Perimeter of the rectangular field = 180 m

• In one round Mahesh will cover 180 m.

Mahesh goes 10 times around it.

So, in ten round he will cover $10$ × $1800$ m $= 1800$ m

• Mahesh cover 1800 m distance when he goes ten times around the rectangular field of dimensions 50 m × 40 m.

To know more about the concept please go through the links

https://brainly.in/question/26029271

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