Question

A rectangular field is 50m by 40m.It has two roads through its centre ,running parellel to its sides .The width of the longer and shorter roads are 2m and 2.5m respectively .Find the area of the roads and the roads and the area of the remaining portion of the field.

Answer 1

Answer:

Step-by-step explanation:

Area of the longer road=2×50=100m^2

Area of the smaller Road =

2.5×40= 100 m^2

area of fields=50×40=2000m^2

area common to both the road

=2.5×2=5m^2

area of roads=200-5=195

=1805m^2=ANSWER

Answer 2

Given:

The width of longer road = 2m

The width of shorter road = 2.5m

The rectangular field is of 50m by 40m

To find:

The “area of Road” and the “remaining portion” of the road

Answer:

The “area of the longer road” $=50 \times 2=100 m^{2}$

The “area of the shorter road” $=40 \times 2.5=100 m^{2}$

“Total area of the rectangular field” $=2 \times 2.5=5 \mathrm{m}^{2}$

“Area common” to both the roads $=2 \times 2.5=5 \mathrm{m}^{2}$

“Total Area of the roads” $=100+100-5=195 \mathrm{m}^{2}$

“Area of the remaining portion” of the field $=2000-195=1805 \mathrm{m}^{2}$