A rectangular field is 6
0 m by 50 m. It has two crossroads through its centre, running parallel to its
sides. The width of the longer and the shorter roads are 2 m and 2.7 m respectively. Find the area
of the roads and the area of the remaining portion of the field.
Answers
Answered by
15
Area of the Field = L x B
=60 x 50 = 3000 m sq
Area of crossroad 1 = L x B
= 2 x 60 = 120 m sq
Area of crossroad 2 = L x B
= 2.7 x 50 = 135
total area of crossroads = 255 m sq
Subtracting the area once where both roads meet because it has been calculated twice,
area common in both roads meet = 2 x 2.7
= 5.4 m sq
subtracting the common area from total area to get real area of crossroads= 255 -5.4
= 249.6 m sq
area of the remaining portion = 3000 - 249.6
= 2750.4 m sq
Answered by
1
Step-by-step explanation:
Area of the longer road =60×2=120m
Area of the shoter road =50×2.7=135m
Area of the common road =2×2.7=5.4m
Area of the roads =(120+135-5.4)=249.6m
Area of the rectangular field =60×50= 3000m
Area of the remaining portion of the field =[3000-249.6]m=2750.4m
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