Question

a rectangular field is 60 m wide while its perimeter is 320 my. if laying of grass costs 7.50 per square meter, how much would it cost for grass to be laid on the field leaving a bare path 8 m wide all around the field

Answer 1

b=60m
p=320m
now,
2(l+b)=320
l+60=160
l=160-60
l = 100m
now,
new length =100-(2×8)
=84m
new bredth=60 -16=44m
area=84×44=3,696 m squre
cost =3,696×7.5=27,720

Answer 2

Answer:

$38070$

Step-by-step explanation:

Width of rectangular field = 60 m

Perimeter = 320m

Perimeter = $2(Length+Breadth)$

So, $320=2(Length+60)$

$160=Length+60$

$100=Length$

Since we are given that  a bare path 8 m wide all around the field

So, the length of the field which is needed to be covered with grass = 100-(3+3)=94 m

Width of the field which is needed to be covered with grass = 60-(3+3)=54 m

Thus the area which is needed to be covered with grass = $Length \times width$

                                                                                              = $94 \times 54$  

                                                                                               = $5076m^2$  

Cost of laying grass 1 m square = 7.50

So, cost of laying grass on 5076 square meter = $7.50 \times 5076$

                                                                               = $38070$

Hence it would cost $38070 for grass to be laid on the field leaving a bare path 8 m wide all around the field.