Question

A rectangular field is 68 m long and 20 m wide. How many right triangular flower beds, whose sides containing the right angle measure 17 m and 5 m, can be laid in this field?​

Answer 1

$\huge {\underline {\underline \pink{ƛƝƧƜЄƦ}}}$

Given

• Length of field = 68m
• Breadth of field = 20m
• Base of triangle = 17m
• Height of triangle = 5m

To Calculate

• No. of flower beds can be laid in field

Solution

Length = 68m

Breadth = 20m

$\bf Area \: of \: field = l \times b$

$\bf Area \: of \: field =68m \times 20m$

$\bf Area \: of \: field = 1360{m}^{2}$

Base of triangle = 17m

Height of triangle = 5m

$\bf Area \: of \: Flower \: bed = \frac{1}{2} \times b \times h$

$\bf Area \: of \: Flower \: bed = \frac{1}{2} \times 17 \times 5$

$\bf Area \: of \: Flower \: bed =42.5 {m}^{2}$

No. of flower beds can be laid in field are

$\bf = Area \: of \: Field \div Area \: of \: Flower \: bed$

$\bf = 1360 \div 42.5$

$\bf = \: 32$

Hence, 32 flower beds can be laid in field.

Answer 2

Answer:

ABOVE ANSWER IS WRONG ONCE CHECK AGAIN.

34

Step-by-step explanation:

AREA OF RECTANGULAR FIELD=L×B

=68×20

=1460m²

AREA OF TRIANGLE FLOWER BEDS=1/2×B×H

=1/2×5×17

=42.5m²

Two triangles combined at hypotenuse can form a rectangle.

There fore, area of two triangles =42.5×2=85m²

No. of triangles can be filled in rectangle=area of rectangular fueld/area of 2 triangles =1460/85=17

so, no. 2 triangles together(a reactangle)=17

no. one triangle=17×2=34.

SO, NO. TRIANGLES CAN BE FILLED IN RECTANGULAR FIELD IS 34.