Question

A rectangular field is 70m long and 60m broad. A well of dimensions 14m×8m×6m is dug outside the field and the earth dug out from this well is spread evenly on the field. how much will the earth level rise?

Answer 1

Suppose the rise in the earth level is h.
Dimensions of the well are 14m × 8m × 6m .
So volume of the earth dug out = volume of the well = 14 m × 8 m ×6 m = 672 m3
Length and breadth of rectangular field are 70 m and 60 m respectively.
Now the volume of the earth dug out is equal to the product of the area of rectangular field and the rise in the earth level.
So we have;
70×60×h = 672⇒4200×h = 672⇒h = 6724200 = 0.16 m
So, rise in the earth level = 0.16 m = 0.16×100 = 16 cm

Answer 2

Answer:

16cm or 0.16m

Step-by-step explanation:

Suppose the rise in the earth level is h. Dimensions of the well are 14m x 8m x 6m .

So volume of the earth dug out = volume of the well = 14 m x 8 m x6 m = 672 m3 Length and breadth of rectangular field are 70 m and 60 m respectively. Now the volume of the earth dug out is equal to the product of the area of

rectangular field and the rise in the earth

level.

So we have;

70x60xh = 672 4200 xh = 672-h =

6724200 = 0.16 m

So, rise in the earth level = 0.16 m =

0.16*100 = 16 cm

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