a rectangular field is 72m by58m. Amar walks round it at the rate of 3km per hour.what time will he take in taking 2 rounds
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Answered by
6
Dimensions of a rectangular field= 72cm y 58cm
perimeter of the rectangular field= 2( l+b )
=2×( 72+58)
= 2×130
= 260cm
∴ Distance taken by Amar in taking two rounds= 2×260m
= 520m
Speed of Amar= 3km/hr
=3×1000/3000 m/sec
= 5/6 m/sec
Total time taken by Amar to cover the distance= Distance/speed
= 520/5/6 = 520×5/6
= 104×6
= 104×6/60 min.
= 10.4 min.
perimeter of the rectangular field= 2( l+b )
=2×( 72+58)
= 2×130
= 260cm
∴ Distance taken by Amar in taking two rounds= 2×260m
= 520m
Speed of Amar= 3km/hr
=3×1000/3000 m/sec
= 5/6 m/sec
Total time taken by Amar to cover the distance= Distance/speed
= 520/5/6 = 520×5/6
= 104×6
= 104×6/60 min.
= 10.4 min.
thakurpooja97:
plzz help me out... where did u find 3000 in speed of amar
Answered by
23
length=72 m
breadth=58 m
perimeter= 2(l+b)
=2*(72+58)
=2*130
=260m
total distance to be covered=2 rounds=2*260m=520m
speed=3km/hr=3*5/18=5/6. m/s
time taken = distance/speed
=520*6/5=3120/5
=624 sec
=10 minutes 24 sec
breadth=58 m
perimeter= 2(l+b)
=2*(72+58)
=2*130
=260m
total distance to be covered=2 rounds=2*260m=520m
speed=3km/hr=3*5/18=5/6. m/s
time taken = distance/speed
=520*6/5=3120/5
=624 sec
=10 minutes 24 sec
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