A RECTANGULAR FIELD IS 75M BY 58M.AMAR WALKS ROUND IT AT THE RATE OF 3 KM PER HOUR . WHAT TIME WILL HE TAKE IN TAKING 2 ROUNDS.
Answers
Step-by-step explanation:
Given, rectangular field is 72 m by 58 m.
Therefore, perimeter of rectangular field = 2(l + b) = 2(72 + 58) m = 260 m.
Distance covered by Amar in 1 round is equal to the perimeter of the rectangle.
Now it is also given that Amar walks around the rectangular field so it covers 260 m in one round.
Therefore, the total distance covered by Amar in 2 rounds = 2 x 260 m = 520 m.
Also we have, Distance = Speed × Time
Speed of Amar = 3 km/h =3×1000/3600
m/s {1 km = 1000 m and 1 h = 3600 s}
= 56m/s
Thus, we can say that Amar covers 5/6 meter in 1 second
Therefore, he covers 520 m in 560/5/6 second = 560×6/5s = 424 s =424/60minutes = 10.4 minutes {1 minute = 60 second)
Step-by-step explanation:
Perimeter of the field = 2(75+58) = 266m
Speed = 3km/hour = 3 ×5/18 = 5/6 m/s
Time taken in 1 round = Distance/speed
= 266/5/6 = 266×6/5 = 319.2 sec
Time taken in 2 rounds = 2 × 319.2 = 638.4 sec