a rectangular field is 90m long and 45m wide. find the ratio of the length to its width.
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Through a rectangular field of length 90 m and breadth 60 m two roads are constructed which are parallel to the sides and cut each other right angles through the centre of the fields. If the width of each road is 3 m, find the cost of constructing the roads at the rate of Rs. 110 per m
2
.
Medium
Solution
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Given length of field = 90 m
width of field = 60 m.
Area of field =90×60
Area =5400m
2
length of road GEFH = 90 m.
length of road ABCD = 60 m.
width of each road = 3m [Given].
Area of roads =ar(ABCD)+ar.(GEFH)−ar(LIJK)
=90×3+60×3−3×3
=270+180−9
Area of roads =441m
2
.
∴ Area covered by roads =441m
2
.
cost of construction of roads =441×10
Total cost =4410Rs.
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Answer:
a rectangular field is 90m long and 45m wide. find the ratio of the length to its width.