Math, asked by Sameer3545O, 11 months ago

A rectangular field is dimensions 30m and 15.5m. two path run parallel to the sides of the rectangle through the centre of the field. The width of the longer path is 1.4m and that the shorter path is 2m.find the area of the path ,and the cost of cementing the path at the rate of ₹70 per square metre

Answers

Answered by TanikaWaddle
22

area of the path =  70.2 m²

cost of cementing the path =  Rs. 4914

Step-by-step explanation:

dimensions of A rectangular field  30 m and 15.5 m

The width of the longer path is 1.4 m and that the shorter path is 2 m

area of the rectangle ABCD = length × breadth

= 30×15.5

= 465 m²

length of the longer path = 30 m

breadth of the longer path = 1.4 m

area of the longer path EFGH= length × breadth

= 30×1.4

= 42 m²

length of the shorter path = 15.5 m

breadth of the shorter path = 2 m

area of the shorter path IJKL=length × breadth

= 15.5 ×2

= 31 m²

area of the common path MNOP  = 1.4×2= 2.8 m²

area of the path = (area of the longer path + area of the shorter path )- area of the common path

area of the path =(42+31)- 2.8

= 73-2.8

= 70.2 m²

cost of cementing the path 1 m² = Rs. 70

cost of cementing the path 70.2 m² = 70.2×70 = Rs. 4914

hence, area of the path =  70.2 m²

cost of cementing the path =  Rs. 4914

#Learn more:

https://brainly.in/question/7527359

Attachments:
Answered by alokbhatia8778
2

Answer:

Step-by-step explanation:

area of the path =  70.2 m²

cost of cementing the path =  Rs. 4914

Step-by-step explanation:

dimensions of A rectangular field  30 m and 15.5 m

The width of the longer path is 1.4 m and that the shorter path is 2 m

area of the rectangle ABCD = length × breadth

= 30×15.5

= 465 m²

length of the longer path = 30 m

breadth of the longer path = 1.4 m

area of the longer path EFGH= length × breadth

= 30×1.4

= 42 m²

length of the shorter path = 15.5 m

breadth of the shorter path = 2 m

area of the shorter path IJKL=length × breadth

= 15.5 ×2

= 31 m²

area of the common path MNOP  = 1.4×2= 2.8 m²

area of the path = (area of the longer path + area of the shorter path )- area of the common path

area of the path =(42+31)- 2.8

= 73-2.8

= 70.2 m²

cost of cementing the p#Learn more:

brainly.in/question/7527359

ath 1 m² = Rs. 70

cost of cementing the path 70.2 m² = 70.2×70 = Rs. 4914

hence, area of the path =  70.2 m²

cost of cementing the path =  Rs. 4914

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