A rectangular field is of dimension 20 m x15 m. Two paths run parallel to the sides of
the rectangle through the centre of the field. The width of the longer path is 2 m and
that of the shorter path is 1 m. Find (i) the area of the paths (ii) the area of the
remaining portion of the field (iii) the cost of constructing the roads at the rate of 10
per sq.m
Answers
rectangle through the centre of the field. The width of the longer path is 1.7 m ...
The area of the paths is 53 m²
The area of the remaining portion of the field is 247 m².
The cost of constructing the roads at the rate of 10 per sq.m is Rs. 530.
Step-by-step explanation:
Dimensions of rectangular field is 20 m x 15 m
The width of the longer path is 2 m and that of the shorter path is 1 m
Step 1:
The area of the rectangle ABCD = length * breadth = 20 * 15 = 300 m²
Area of the shorter path IJKL = 15 * 1 = 15 m²
Area of the londer path EFGH = 20 * 2 = 40 m^2
and,
Area of the middle common path MNOP = 2 * 1 = 2 m²
∴ Area of the paths is given by,
= [Area of the shorter path IJKL] + [Area of the londer path EFGH] - [Area of the middle common path MNOP]
= 15 + 40 - 2
= 53 m²
Step 2:
∴ Area of the remaining protion is given by,
= [The area of the rectangle ABCD] - [Area of the paths]
= 300 - 53
= 247 m²
Step 3:
The rate of constructing the roads is given as Rs. 10 per sq. meter
∴ The total cost of constructing the roads is given by,
= 53 m² * Rs. 10
= Rs. 530
------------------------------------------------------------------------------
Also view:
A tank is 3/5 full of water 50litres more are required to fill it up how many litres can the tank hold Solve the questions
https://brainly.in/question/3325387
The area of a circular Field is 5041pi metres square find the perimeter of a circular field
https://brainly.in/question/1742383
The area of a circular field is 13.86 m sq. What is the cost of fencing it at a rate of Rs. 20.5 per cm ?
https://brainly.in/question/3907284
