A rectangular field is of dimensions 30 m x 15.5 m. Two paths run parallel to the sides of the rectangle
through the centre of the field. The width of the longer path is 1.4 m and that the shorter path is 2m. Find
(a) the area of the paths, and
(b) the cost of cementing the paths at the rate of * 70 per m².
Answers
Answer:
area of the path = 70.2 m²
cost of cementing the path = Rs. 4914
Step-by-step explanation:
dimensions of A rectangular field 30 m and 15.5 m
The width of the longer path is 1.4 m and that the shorter path is 2 m
area of the rectangle ABCD = length × breadth
= 30×15.5
= 465 m²
length of the longer path = 30 m
breadth of the longer path = 1.4 m
area of the longer path EFGH= length × breadth
= 30×1.4
= 42 m²
length of the shorter path = 15.5 m
breadth of the shorter path = 2 m
area of the shorter path IJKL=length × breadth
= 15.5 ×2
= 31 m²
area of the common path MNOP = 1.4×2= 2.8 m²
area of the path = (area of the longer path + area of the shorter path )- area of the common path
area of the path =(42+31)- 2.8
= 73-2.8
= 70.2 m²
cost of cementing the path 1 m² = Rs. 70
cost of cementing the path 70.2 m² = 70.2×70 = Rs. 4914
hence, area of the path = 70.2 m²
cost of cementing the path = Rs. 4914
Answer:
(a) 42m² and 60 m²
(b) ₹2,940 and ₹4,200
Step-by-step explanation:
(See image)
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