Question

a rectangular field is of length 69/4m and width 31/2 there is a house in the centre of the field , which is square of side 49/4m.find the perimeter of both rectangular field and the house respectively.​

Answer 1

Answer:

Step-by-step explanation:

total perimeter of outer rectangle 69/4*2 +31/2*2 65.5

perimeter on inner square or house = 49/4*4= 49

65.5 and 49 is the answer