Question

a rectangular field is of size 30 M butterfly 20 metre two parts Run parallel to the sides of the rectangle through the centre of the fit the width of the larger and shorter path and 3 and 2 metre respectively find the area of the path also find the area of remaining portion of the and answer should be 124​

Answer 1

Answer:

Length of rectangular field, l=25m

Width of rectangular field, b=16.4m

Length of the shorter

Length of the shorter path, 1¹=16.4m

Width of the shorter path, b¹=2m

Length of the longer path,1²=25m

Width of the longer path,b²=1.7m

Area of shorter path, =A¹=1¹=b¹

=(16.4×2)m

=32.8m²

Area of longer path, A²=l²×b²

=(26×1.7)m²

=42.5m²

Thus, Area of the path, Path P=A¹×A²−Area of common path

=(32.8+42.5)m²–(2×1.7)m²

75.3m−3.4m²

=71.9m²

Area of the rectangular field=A=l×b

=(25×16.4)m²

=410m²

Hence area of the remaining position of the field.

=A−P

=(410−71.9)m²

=338.1m²

hope helps u user

Step-by-step explanation:

you can refer the attachment also

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