a rectangular field is of the size 30 M by 20 m. two paths Run parallel to the sides of the rectangle through the centre of the field. the width of the larger and shorter path are 3 m and 2 m respectively. find the area of the path. also, find the area of remaining portion of the field.
Answers
Answer:
Solve this question with this method
Step-by-step explanation:
The area of the path is 124 m² and also the area of the remaining portion of the field is 476 m².
Step-by-step explanation:
Step 1:
Dimensions of rectangular field is 30 m x 20 m
The width of the longer path is 3 m and that of the shorter path is 2 m.
The area of the rectangle ABCD = length * breadth = 30 * 20 = 600 m²
Area of the shorter path IJKL = 20 * 2 = 40 m²
Area of the londer path EFGH = 30 * 3 = 90 m²
and,
Area of the middle common path MNOP = 3 * 2 = 6 m²
Step 2:
Thus,
Area of the paths is given by,
= [Area of the shorter path IJKL] + [Area of the londer path EFGH] - [Area of the middle common path MNOP]
= 40 + 90 - 6
= 124 m²
And,
Area of the remaining portion is given by,
= [The area of the rectangle ABCD] - [Area of the paths]
= 600 - 124
= 476 m²
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