Question

A rectangular field length is 25 5/6m and breadth is 20 3/5m. What is the perimeter of the field?

Answer 1

Answer:-4986m

perimeter of a rectangular field = 2(l+b)

ATQ:-

length=255 /6

breadth = 203/5

2(255/6+203/5)

=2(1275+1218)

=2(2493)

=4986

Answer 2

Perimeter of given field is 92.9 m.

Given - Length and breadth

Find - Perimeter

Solution - Perimeter = 2 (length + breadth)

Length = $25 \frac{5}{6} \: m$

Length = $\frac{(6 \times 25) + 5}{6}$

Length = $\frac{155}{6} m$

Breadth = $20 \frac{3}{5}$

Breadth = $\frac{(5 \times 20) + 3}{5}$

Breadth = $\frac{103}{5}m$

Perimeter = $2( \frac{155}{6} + \frac{103}{5} )$

Taking LCM, we get 30

Perimeter = $2( \frac{155 \times 5 + 103 \times 6}{30} )$

Perimeter = $2( \frac{775 + 618}{30} )$

Perimeter = 2*46.4

Perimeter = 92.9 m

Hence, the perimeter of field is 92.9 m.

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