Question

A rectangular field measures 275 m by 165 m. It is to
be fenced with three rounds of wire. What length of
wire is needed ?​

Answer 1

Answer:

2640m

Step-by-step explanation:

perimeter of field is 2(L+B)

=2(275+165)

=2(440)

=880

wire needed is 3*880=2640m

Answer 2

Solution :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 275 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 165 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

The length of the rectangle is 275 m ; and the breadth is 165 m .

Perimeter of the rectangle :

> 2[ Length + Breadth ]

> 2[ 275 + 165 ]

> 2[ 440 ]

> 880 m.

Thus, the perimeter of the rectangle is 8880m. This is fenced with three rounds of wire.

Length of wire :

> 3 x Perimeter

> 3 x 880

> 2640 m .

This is the required answer.

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