A rectangular field measures 400m by 550m. What is the perimeter of the field?
a. in meters b. in kilometers
Please show solving.
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Answers
Perimeter = 2(l+b)
= 2 (400+550) = 2×950 = 1900m
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The perimeter of a rectangular piece of land = 2(Length + Breadth)
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)= 2.4 km
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)= 2.4 km\because1km\ =\ 1000m∵1km = 1000m
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)= 2.4 km\because1km\ =\ 1000m∵1km = 1000m\therefore0.24\ =\ 1000\times0.24=2400∴0.24 = 1000×0.24=2400 m.
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)= 2.4 km\because1km\ =\ 1000m∵1km = 1000m\therefore0.24\ =\ 1000\times0.24=2400∴0.24 = 1000×0.24=2400 m.Since 4 rows of wire is required.
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)= 2.4 km\because1km\ =\ 1000m∵1km = 1000m\therefore0.24\ =\ 1000\times0.24=2400∴0.24 = 1000×0.24=2400 m.Since 4 rows of wire is required.\therefore2400\times4=9600∴2400×4=9600 m.
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)= 2.4 km\because1km\ =\ 1000m∵1km = 1000m\therefore0.24\ =\ 1000\times0.24=2400∴0.24 = 1000×0.24=2400 m.Since 4 rows of wire is required.\therefore2400\times4=9600∴2400×4=9600 m.\therefore9600\ m\ =\ 9.6\ km∴9600 m = 9.6 km
The perimeter of a rectangular piece of land = 2(Length + Breadth)= 2(0.7+0.5)= 2(1.2)= 2.4 km\because1km\ =\ 1000m∵1km = 1000m\therefore0.24\ =\ 1000\times0.24=2400∴0.24 = 1000×0.24=2400 m.Since 4 rows of wire is required.\therefore2400\times4=9600∴2400×4=9600 m.\therefore9600\ m\ =\ 9.6\ km∴9600 m = 9.6 kmTherefore, length of wire required is 9.6 km or 9600 m
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