A rectangular field measuring 36 m x 24 m is it be surrounded externally by a path which is 25 m wide.
the cost of constructing this path at the rate of 4.5 per m.
Answers
=Area of rectangle = L x B
= Area of rectangle = 50 x 36
=Area of rectangle = 1800 m²
=X = 1800 m²
We know that length and breadth increase by 2 m from their both ends.
= L = 50 + 2 + 2 = 54 m.
= B = 36 + 2 + 2 = 40 m.
We know formula of
=Area of rectangle + path = L x B
=Area of rectangle + path
= 54 x 40
Area of rectangle + path
= 2160 m²
X = 2160 m²
Area of path =( Z ) - (X)
Area of path = 2160 - 1800
Area of path = 360 m²
To finding cost of surfing the path
Area x 16 = 360 x 16= Rs 5760
Hence cost of levelling the path is Rs 5760
..QUESTION..
A rectangular field measuring 36 m × 24 m is surrounded externally by a wide path which is 25 m wide . Find the cost of constructing the path at the rate of Rs 4.5 per m
..ANSWER..
Given here ,
ㅤㅤㅤ➪ Length of field = 36 m
ㅤㅤㅤ➪ Breadth of field = 24 m
ㅤㅤㅤ➪ Width of path = 35 m
ㅤㅤㅤ➪ Rate of constⁿ of path = rs 4.5
☯︎ We know that » Perimeter(rectangle) = 2 ( l + b )
•°• A / Q
ㅤㅤㅤ➪ Perimeter of the field
ㅤㅤㅤ➪ 2 ( l + b )
ㅤㅤㅤ➪ 2 ( 36 + 24 )
ㅤㅤㅤ➪ ( 2 × 36 ) + ( 2 × 24 )
ㅤㅤㅤ➪ 73 + 48
ㅤㅤㅤ➪ 121ㅤㅤㅤ --------------»
•°• Perimeter of field = 121 m
★ Now , Perimeter of field along with path =
☯︎ Length of " " " " = 36 + 25 = 61 m
☯︎ Breadth of " " " " = 24 + 25 = 49 m
★ Add 25 × 2 to length
☯︎ Length = 61 + 50 = 111 m
•°• Perimeter of field with path ➪
ㅤㅤㅤ➪ 2 ( l + b )
ㅤㅤㅤ➪ 2 ( 111 + 49 )
ㅤㅤㅤ➪ ( 2 × 111 ) + ( 2 × 49 )
ㅤㅤㅤ➪ 222 + 98
ㅤㅤㅤ➪ 320 ㅤㅤㅤ------------------»
•°• Perimeter(field) with path = 320 m
•°• Perimeter of the path =
➪ perimeter(field+path) - perimeter(field)
ㅤㅤㅤ➪ 320 m - 121 m
ㅤㅤㅤ➪ ( 320 - 121 ) m
ㅤㅤㅤ➪ 199 m
★ Now ,
☯︎ Rate of constructing path = Rs 4.5 / m
•°• A / Q
➪ Cost of constructing 1 m = Rs 4.5
➪ Cost of constructing 121 m = 4.5 × 121
➪ㅤ"ㅤㅤ"ㅤㅤㅤ"ㅤㅤㅤ"ㅤㅤ" = 544.5
•°• Construction(road) cost = Rs 544.5
ㅤㅤㅤ꧁ ʙʀᴀɪɴʟʏ×ᴋɪᴋɪ ꧂
ㅤㅤㅤ