A rectangular field of dimension 160×80m has four paths through it, two paths of 2m parallel to the breadth and two paths each of 3m width parallel to the length find the area of the paths
Answers

The area of the four paths running parallel to length and breadth of the field is 1256 m².
Step-by-step explanation:
Dimensions of the rectangular field:
Length, L = 160 m
Breadth, B = 80 m
Dimension of 2 paths running parallel to the breadth:
Width, w1 = 2 m
Dimesion of the 2 paths running parallel to the breadth:
Width, w2 = 3 m
Therefore,
Area of the 2 paths parallel to the length = 2 * [L * w2] = 2 * [160 * 3] = 960 m²
Area of the 2 paths parallel to the breadth = 2 * [B * w1] = 2 * [80 * 2] = 320 m²
Area of the common paths between the 4 paths = 4 * [w1 * w2] = 4 * [2 * 3] = 24 m²
Thus,
The area of the paths is given by,
= [Area of the 2 paths parallel to the length] + [Area of the 2 paths parallel to the breadth] – [Area of the common paths between the 4 paths]
= 960 + 320 – 24
= 1256 m²
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