Question

A rectangular field of dimensions 160 m×80m has four paths through it, two paths of two metre parallel to the breadth and two paths is of 3 m width parallel to the length. (1) Find the area of the path. (2) Find the area of the remaining portion of the park. (3)Find the cost of levelling of the field at the cost of Rs.3 per square meter.​

Answer 1

1.Area of path=$1256 m^2$

2.Area of remaining portion of park=$11544 m^2$

3.Cost of leveling of the field=Rs 34632

Step-by-step explanation:

Breadth of rectangle=80 m

Length of rectangle =160 m

Area of park =$length\times breadth$

Area of park=$160\times 80=12800 m^2$

Width of one path which is parallel to breadth=2 m

Area of 1 path =$2\times 80=160 m^2$

Area of 2 paths parallel to breadth=$2\times 160=320 m^2$

Area of two paths parallel to length=$2\times 3\times 160=960m^2$

Area of overlapping portion=$4(2\times 3)=24 m^2$

Using formula : Area of square=$side \times side$

1.Area of paths=$320+960-24=1256 m^2$

2.Area of remaining portion of park=Area of park-area of path

Area of remaining portion of park=$12800-1256=11544 m^2$

3.Cost of leveling of  1 square meter of the field=Rs 3

Cost of leveling of  1 square meter of the field=$3\times 11544=Rs 34632$

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