Question

A rectangular field of dimensions 28 mx 6 m is to be ploughed by a tractor. If the tractor consumes 2 / of
diesel for ploughing every 12 m of the field. Find the quantity of diesel required to plough the entire field.​

Answer 1

Answer:

Step-by-step explanation:

Case 1 :

Tractors = 6

Days = 4

Area ploughed by one tractor = 120 hec

Area ploughed by all 6 tractors in a day = 6 × 120 = 720 hec

So, area ploughed by the tractors in 4 days = 720 × 4 = 2880 hec

So, total area of the field = 2880 hec

Case 2:

Tractors = 6 - 2 = 4

Days = 5

Area ploughed by one tractor = ?

Area of the field = 2880 hec

So,

2880 = Area ploughed by one tractor × Total tractors × Total days

2880 = Area ploughed by one tractor × 4 × 5

Area ploughed by one tractor = 2880/20

So, area ploughed by one tractor = 144 hec

Answer 2

Answer:

28L

Step-by-step explanation:

Area of field=28*6=168m^2

litre used in ploughing 12m^2 of land=2

litre used for 1m^2 of land=2/12

litre used for 168m^2 land,=2*168/12=28