Math, asked by anabiyaehtasham57, 1 day ago

a rectangular field of length 19 m and breadth 62 roads are constructed which are parallel to the side and cut each other at right angles through the centre of the field is the width of each road is 3 m find the area covered by the roles and also find the cost of constructing the road at the rate of 110 per metre square​

Answers

Answered by lovestudies58
0

Answer:

Length of rectangular field - 90 m

Breadth of rectangular field - 60 m Area of road which is constructed parallel length

- 90 mx 3 m - 270 m² Area of road which is constructed parallel to breadth

= 60 mx 3 m - 180 m²

3m

-50

90 m

+3m+

Area of square common in two roads

-3mx3m-9 m²

Now,

(i) Area covered by the roads

-270 m² + 180 m²-9 m²

(]

U

= 450 m² -9 m² = 441 m² (ii) Cost of constructing the roads at the rate of 110 per m²

-(441 110)=48,510.

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Answered by sabarish13052011
0

Answer:

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lovestudies58

Answer:

Length of rectangular field - 90 m

Breadth of rectangular field - 60 m Area of road which is constructed parallel length

- 90 mx 3 m - 270 m² Area of road which is constructed parallel to breadth

= 60 mx 3 m - 180 m²

3m

-50

90 m

+3m+

Area of square common in two roads

-3mx3m-9 m²

Now,

(i) Area covered by the roads

-270 m² + 180 m²-9 m²

(]

U

= 450 m² -9 m² = 441 m² (ii) Cost of constructing the roads at the rate of 110 per m²

-(441 110)=48,510.

Step-by-step explanation:

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