a rectangular field with length (4a-2)m and breadth 2a m requires 4 (a+2)m of rope for fencing around it. Find its dimensions
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given,
length=4a-2
breadth=2a
perimeter=4a+8
we know that
perimeter of rectangle is 2(l+b)
therefore
4a+8=2(2a+4a-2)
4a+8=2(6a-2)
4a+8=12a-4
8+4=12a-4a
12=8a
a=3/2
therefore
length =4(3/2)-2
=6-2=4m
breadth=2(3/2) =3m
length=4a-2
breadth=2a
perimeter=4a+8
we know that
perimeter of rectangle is 2(l+b)
therefore
4a+8=2(2a+4a-2)
4a+8=2(6a-2)
4a+8=12a-4
8+4=12a-4a
12=8a
a=3/2
therefore
length =4(3/2)-2
=6-2=4m
breadth=2(3/2) =3m
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