Question

a rectangular filed is 28 metre long and 8 metre wide how many triangular flower bed each of base 7 and altitude 6 metrer be laid in the field​

Answer 1

Question:

A rectangular field is 28 m long and 18 m wide. How many triangular flower beds each of base 7 m and altitude 6 m can be laid on the field?

Answer:

$\bigstar{\bold{Number\:of\:flower\:beds=24}}$

Step-by-step explanation:

$\Large{\underline{\sf{Given:}}}$

• Length of rectangular field = 28 m
• Width/Breadth of the rectangular field = 18 m
• Base of the triangular flower bed = 7 m
• Altitude of the triangular flower bed = 6 m

$\Large{\underline{\sf{To\:Find:}}}$

• The number of triangular flower beds that can be laid on the rectangular field

$\Large{\underline{\sf{Solution:}}}$

➔ Here we have to find how many triangular flower beds can be laid on the rectangular field.

➔ First finding the area of the rectangular field,

➔ Area of a rectangle is given by,

    Area of a rectangle = l × b

    where l is the length

    and b is the breadth

➔ Substitute the data,

    Area of the rectangular field = 28 × 18

    Area of the rectangular field = 504 m²

➔ Hence area of the rectangular field is 504 m².

➔ Now finding the area of the triangular flower bed,

➔ Area of a triangle id given by,

    Area of a triangle = 1/2 × b × h

    where b is the base of the triangle

    h is the height or the altitude

➔ Substitute the data,

    Area of the triangular flower bed = 1/2 × 7 × 6

    Area of the triangular flower bed = 7 × 3

    Area of the triangular flower bed = 21 m²

➔ Hence area of the flower bed is 21 m².

➔ Now finding the number of flower beds,

   Number of flower beds = Area of field/Area of flower bed

➔ Substitute the data,

    Number of flower beds = 504/21

   Number of flower beds = 24

➔ Hence 24 flower beds can be laid on the rectangular field.

    $\boxed{\bold{Number\:of\:flower\:beds=24}}$

Answer 2

$\huge{\underline{\bf{Given:-}}}$

▢Length of Rectangular Field = 28m

▢Breadth of Rectangular Field = 8m

▢Height of Triangular flower bed = 6m

▢Base of Triangular flower bed = 7m

$\huge{\underline{\bf{Find:-}}}$

▢Number of Triangular flower bed laid in the field

$\huge{\underline{\bf{Solution:-}}}$

Here, we know that

$\large{\underline{\boxed{\sf Area \: of \: rectangle = length \times breadth}}}$

where,

• Length, l = 28m
• Breadth, b = 8m

So,

$\dashrightarrow\sf Area \: of \: rectangle = l \times b$

$\dashrightarrow\sf Area \: of \: rectangle = 28\times 8$

$\dashrightarrow\sf Area \: of \: rectangle = 224 {m}^{2}$

$\therefore\sf Area \: of \: rectangle = 224 {m}^{2}$

___________________________

we, know

$\large{\underline{\boxed{\sf Area \: of \: triangle = \dfrac{1}{2} \times b \times h}}}$

where,

• Base, b = 7m
• Height, h = 6m

So,

$\dashrightarrow\sf Area \: of \: triangle = \dfrac{1}{2} \times b \times h$

$\dashrightarrow\sf Area \: of \: triangle = \dfrac{1}{2} \times7 \times6$

$\dashrightarrow\sf Area \: of \: triangle = \dfrac{1}{2} \times42$

$\dashrightarrow\sf Area \: of \: triangle = \dfrac{42}{2}$

$\dashrightarrow\sf Area \: of \: triangle = 21 {m}^{2}$

$\therefore\sf Area \: of \: triangle = 21 {m}^{2}$

___________________________

Now,

$\large{\boxed{\sf No. \: of \: flower \: bed = \dfrac{Area \: of \: Rectangle}{Area \: of \: Triangle}}}$

where,

• Area of Rectangle = 224m²
• Area of Triangle = 21m²

So,

$\dashrightarrow\sf No. \: of \: flower \: bed = \dfrac{224}{21}$

$\dashrightarrow\sf No. \: of \: flower \: bed =10.6(approx.)$

$\dashrightarrow\sf No. \: of \: flower \: bed =11$

Hence, No. of flower bed laid in Rectangular field = 11