Math, asked by akankshaprakash0609, 9 months ago

A rectangular filed is 70m long and 60m broad. A well of dimensions 14m x 8m x 6m is dug outside the field and the earth dug from this well is spread evenly on the field. How much will the earth level rise? Explain.

Answers

Answered by De20va07
0

Answer:

16 cm

Step-by-step explanation:

Suppose the rise in the earth level is h.

Dimensions of the well are 14m × 8m × 6m .

So volume of the earth dug out = volume of the well = 14 m × 8 m ×6 m = 672 m3

Length and breadth of rectangular field are 70 m and 60 m respectively.

Now the volume of the earth dug out is equal to the product of the area of rectangular field and the rise in the earth level.

So we have;

70×60×h = 672⇒4200×h = 672⇒h = 6724200 = 0.16 m

So, rise in the earth level = 0.16 m = 0.16×100 = 16 cm

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