Question

A rectangular floating body 20 m long is 5m wide The water line is 1.5 m above the bottom, if the centre of gravity is 1.8 m from the bottom then the metacentric height will be approximately​

Answer 1

Let G be the center of gravity point.

M be the point above G. B be the point below G. O be the point below B on the rim of floating body.

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M

G (Center of Gravity)

B

O (Point on the rim)

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MB = I / V =  (1/12 x 20 x 5^ 4) / ( 20 x 5 x 1.5 ) = 1.4 m

OB = 1.5 /2 = 0.75

OG = 1.8 m (Given)

BG = OG - OB = 1.8 - 0.75 = 1.05 m

MG (Meta centric) = MB - BG = 1.4 - 1.05 = 0.35 m

Answer 2

Answer:0.34

Explanation: