Question

A rectangular floor of dimensions 10.2 mx 6 m is to be tiled with square
tiles with its side as 60 cm. How many tiles will be required to cover the
floor?​

Answer 1

✬ Tiles = 170 ✬

Step-by-step explanation:

Given:

• Length of rectangular hall is 10.2 m.
• Breadth of hall is 6 m.
• Dimension of square shaped tile is 60 cm.

To Find:

• How many tiles will be required to tile the hall ?

Solution: Let x tiles will be required to tile the rectangular hall.

• To find the value of x , we have to divide the area of rectangular hall by the area of square shaped tile.

Lets find area of hall

★ Ar. of Rectangle = Length × Breadth ★

$\implies{\rm }$ 10.2 m × 6 m

$\implies{\rm }$ 61.2 m²

So, the area of rectangular hall is 61.2 m².

Now finding area of tile but before this change the cm to m.

• 100 cm = 1 m

• 60 cm = 60/100 = 0.6 m

★ Area of Square = Side² ★

$\implies{\rm }$ 0.6 m × 0.6 m

$\implies{\rm }$ 0.36 m²

So, the area of one tile is 0.36 m².

∴ Total no. of tiles required = Ar (Hall/tile)

➼ x = 61.2/0.36

➼ x = 170

Hence , 170 square shaped tiles will be required to tile the rectangular hall.

Answer 2

Answer:

Given :-

• A rectangular hall has length as 10.2 m and breadth = 6 m
• Side of tile = 60 cm

To Find :-

Total tiles required

Solution :-

We know that

Area of rectangle = Length × Breadth

Area = 10.2 m × 6 m

Area = 61.2 m²

Now,

Area of tile = side²

100 cm = 1 m

60 cm = 60/100 = 0.6 m

Area = 0.6²

Area = 0.36 m²

Now,

Total tiles = 61.2/0.36

$\sf \underline {Total \: Tiles = 170 }$