A rectangular floor of dimensions
8.4 m x 5.4 m is to be tiled with right-
triangular marble pieces, with base 40 cm
and height 30 cm. How many marble
pieces will be required to cover the floor?
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Given:
- Dimensions of rectangular floor is 8.4 x 5.4 cm.
- Base of triangle is 40 cm and height is 30 cm.
To Find:
- Marble pieces will be required to cover the floor.
Solution:
First finding the area of rectangular floor.
- Length of floor = 8.4 m or 840 cm
- Breadth of floor = 5.4 cm or 540
★ Area of Rectangle = Length × Breadth
→ Area of floor = (840 × 540) m²
→ 453600 m²
So,
- The area of rectangular floor is 453600 cm².
Now,
- Area of each marble piece that is in form of triangle.
As we know:
★ Area of triangle = 1/2(Base)(Height)
→ Area of marble = 1/2(40)(30)
→ 1 × 20 × 30
→ 600 cm²
∴ Total marble pieces required = Area of floor/Area of marble piece
→ 453600 cm²/600 cm²
→ 756 marble pieces.
Hence,
- Triangular marble pieces will be required to cover the floor = 756.
Anonymous:
Well explained
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