Question

A rectangular floor of length 9m and breadth 6m has black tiles laid in the given pattern. Find the number of tiles laid, if each tile has dimensions 40*10cm.

Answer 1

Answer:

1350 tiles

Step-by-step explanation:

let tiles be n

Area of floor =n × area of 1 tile

900 ×600 = n × 40 × 10

n = 1350

Answer 2

$\bf{\huge{\underline{\boxed{\sf\orange{Answer:\:1350\:tiles}}}}}$

Given:

• In rectangular floor, length = 9 m and breadth = 6 m
• In each  rectangular tile, length = 40 cm and breadth = 10 cm

To Find:

• Total number of tiles needed

Formula used:

$\huge\underline\green{\tt Solution:}$

∵ 1 m = 100 cm.

So,

In rectangular floor, 9 m = 900 cm ; 6 m = 600 cm

→ Area of floor

= 900 × 600

= 540000 cm²

→ Area of each tile

= 40 × 10

= 400 cm²

Now,

Number of tiles needed = $\dfrac{Area\:of\:floor}{Area\:of\:each\:tile}$

$= \frac{540000}{400} \\\\= 1350$

Hence,

1350 tiles are needed.