Question

A rectangular floor of length 9m and breadth 6m has black tiles laid in a pattern. Find the number of tiles laid, if each tile has dimensions 40cm x 10cm.

Answer 1

Step-by-step explanation:

area of floor / area of tile = 9×100 = 900 cm

6×100=600cm

600×900/40×10

60×90/4

15×90

1350 tiles are required to cover the floor.

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Answer 2

Given data : A rectangular floor of length 9m and breadth 6m has black tiles laid in a pattern. Each tile has dimensions 40cm x 10cm.

Solution : Here, a/c to given data;

➜ Length of floor = 9 m

➜ Breadth of floor = 6 m and

Let,

➜ Length of tile = 40 cm

➜ Breadth of tile = 10 cm

Here, we know, 1 m = 100 cm. Hence

➜ Length of tile = 40 cm = 40/100 m = 0.4 m

➜ Breadth of tile = 10 cm = 10/100 m = 0.1 m

Now, by formula of area of rectangle;

➜ Area of floor = Length * Breadth

➜ Area of floor = 9 * 6

➜ Area of floor = 54 m²

Similarly,

➜ Area of tile = Length * Breadth

➜ Area of tile = 0.4 * 0.1

➜ Area of tile = 0.04 m²

Now,

➜ Number of tile = Area of floor/Area of tile

➜ Number of tile = 54/0.04

➜ Number of tile = 1350

Answer : Therefore, 1350 black tiles placed in the pattern are used.