a rectangular floor which measures 15m*8m is to be laid with tiles measuring 50cm*25cm. find the no of tiles required . further if a carpet is laid on a floor so that a space of 1m exist between its edges and the edges of the floor what fraction of a floor is uncovered.
Answers
Answered by
18
Area of the floor =15m *8m
=1500cm*800cm
=1200000 sq. cm
area of one tile=50*25=750 sq. cm
No. of tiles required=1200000/ 750
=16000
space between each edge=1m
therefore the dimensions of the carpet will be (15-2)*(8-2)
area of carpet=l*b
=13*6
=78 sq.m
area of floor uncovered=120m-78m
=52sq.m
Answered by
2
HOPE IT HELPS YOU
MARK AS BRAINLIST
THANKS
Attachments:
Similar questions