a rectangular floor which measures 15m*8m is to be laid with tiles measuring 50cm*25cm . find the number of tiles required. further if a carpet is laid on the floor so that a space of 1m exists between it's edges and the edges of the floor. what fraction the floor is uncovered.
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Area of floor = 1500 x 800 = 1 200 000 cm²
Area of tile = 50 x 25 = 1250 cm²
No. of tiles required = 1 200 000/1250 = 960 tiles
Space = 1m = 100cm; on both sides it will be 200 cm
Area of carpet = (1500 - 200) x (800 - 200) = 780,000 cm²
Uncovered area = 1 200 000 - 780,000 = 420,000 cm²
Fraction uncovered = 420,000 / 1,200,000 = 7/20 or 0.35
Area of tile = 50 x 25 = 1250 cm²
No. of tiles required = 1 200 000/1250 = 960 tiles
Space = 1m = 100cm; on both sides it will be 200 cm
Area of carpet = (1500 - 200) x (800 - 200) = 780,000 cm²
Uncovered area = 1 200 000 - 780,000 = 420,000 cm²
Fraction uncovered = 420,000 / 1,200,000 = 7/20 or 0.35
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