Math, asked by krishdev, 8 months ago

A rectangular garden 115m by 90m
it has two road each 6m wide running in the middle of it.one
paralle to length and other to its breadth.find the cost of constructing the roads at per m sq.​

Answers

Answered by Anonymous
2

Answer:

[This(||) sign is to show that its parallel]

The length of Road || to length is 15m and width 2m.

So Area of road || to length

=15×2=230m²

The length of road || to breadth is 64m and width 2.5m

☆ So the Area of road || to breadth =64×2.5

=160m²

But as you can observe the area common to both roads is taken twice.

☆So the Area of common road

=2×2.5=5m²

☆So the area of road that need gravelling=230+160-5=385m²

☆The price for gravelling=>

385×60=₹23100

Hope it helps you......

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