A rectangular garden has an area of 360 square feet. the length of the garden is 9 feet longer than the width. find the dimensions of the garden in feet.
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Question:-
The area A = 360 square ft.
And the one condition “ 9 ft. longer than it is width.”
Find out, both the dimensions of the rectangular garden = ?
The value of the length L = W + 9
Area A = { Length × width }
360 = { (W + 9) × W }
W ^ 2 + 9W -360 = 0
Now it is a quadratic equations it has two roots.
W ^ 2 + (24–15)W -360=0
W ^ 2 + 24W -15W -360=0
W(W +24)-15(W+24)=0
(W+24)(W-15)=0
There are two value of we get,
(W +24)=0, W = -24 ( not valid value )
If W -15=0, W=15 ft. answer (dimension)
The value of length L = W + 9 = 15+9= 24 ft.
L= 24 ft. answer ( dimension)
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