Question

A rectangular garden has an area of 360 square feet. the length of the garden is 9 feet longer than the width. find the dimensions of the garden in feet.​

Answer 1

Answer:

a = lw = 360

l = w + 9

Substitute:

360 = (w + 9)w

360 = w² + 9w

w² + 9w - 360 = 0

w = 15 (I used the quadratic formula and discarded the negative root.)

l = 24

Answer 2

Question:-

$A \: rectangular \: garden \: has \: an \: area \: of \: 360 \: square \: feet. \: the \: length \: of \: the \: garden \: is \: 9 \: feet \: longer \: than \: the \: width. \: find \: the \: dimensions \: of \: the \: garden \: in \: feet.$

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The area A = 360 square ft.

And the one condition “ 9 ft. longer than it is width.”

Find out, both the dimensions of the rectangular garden = ?

The value of the length L = W + 9

Area A = { Length × width }

360 = { (W + 9) × W }

W ^ 2 + 9W -360 = 0

Now it is a quadratic equations it has two roots.

W ^ 2 + (24–15)W -360=0

W ^ 2 + 24W -15W -360=0

W(W +24)-15(W+24)=0

(W+24)(W-15)=0

There are two value of we get,

(W +24)=0, W = -24 ( not valid value )

If W -15=0, W=15 ft. answer (dimension)

The value of length L = W + 9 = 15+9= 24 ft.

L= 24 ft. answer ( dimension)

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