A rectangular garden is 12 m long and 10 m wide. Surrounding the garden is a paved walk of uniform width. The combined area of the garden and walk is 168 m2. Find the width of the walk.
Answers
Answer:
hey here is ur answer
Step-by-step explanation:
Your equation is
(5+2x)*(12+2x) - 5*12 = 168,
where x is an unknown width of the path.
The equation's left side is the difference between the areas of the larger rectangle and the area
of smaller rectangle which represents the garden.
The right side is the given area of the surrounding path.
Simplify the equation:
4x%5E2+%2B+10x+%2B+24x+%2B+60+-+60 = 168, or
4x%5E2+%2B+34x+-+168 = 0.
Use the quadratic formula to find the roots.
The only root which fits is positive x = 3.5.
Check: (5+2*3.5)*(12+2*3.5) - 60 = 12*19 - 60 = 168. (OK!)
Answer. The width of the path is 3.5 m.
The area of the path is 168 m^2
That is 2(5+2x)*x+24x
Therefore 10x+4x^2+24x=168
4x^2+34x-168=0
2x^2+17x-84=0
(2x-7)(x+12)=0
x=3.5 m. ANSWER.
The whole area is 19*12=228 sq m.