Question

a rectangular garden is 175m long and 96m broad. Find the cost of fencing it at ₹1.50 per metre. Also, find the cost of ploughing it at 50 paise per square metre (please explain step by step) ​

Answer 1

Step-by-step explanation:

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Answer 2

Given :

• Length and Breadth of Rectangular Garden is 175 m and 96 m respectively .

To Find :

• Cost of fencing garden ar rate of Rs.1.50 per m .
• Cost of ploughing garden at 50 paisa per m square .

Solution :

$\longmapsto\tt{Length=175\:m}$

$\longmapsto\tt{Breadth=96\:m}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{2(175+96)}$

$\longmapsto\tt{2(271)}$

$\longmapsto\tt\bf{542\:m}$

So , The Perimeter of Garden is 542 m ....

Now ,

$\longmapsto\tt{Cost\:of\:1\:m=Rs.1.50}$

$\longmapsto\tt{Cost\:of\:542\:m=542\times{1.50}}$

$\longmapsto\tt\bf{Rs.813}$

_______________________

$\longmapsto\tt{Length=175\:m}$

$\longmapsto\tt{Breadth=96\:m}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Rectangle=length\times{breadth}}$

Putting Values :

$\longmapsto\tt{175\times{96}}$

$\longmapsto\tt\bf{16800\:{m}^{2}}$

So , The Area of Garden is 16800 m² ....

Now ,

$\longmapsto\tt{Cost\:of\:1\:{m}^{2}=50\:p=\dfrac{1}{2}r}$

$\longmapsto\tt{Cost\:of\:16800\:{m}^{2}={\cancel{16800}}\times{\dfrac{1}{{\cancel{2}}}}}$

$\longmapsto\tt\bf{Rs.8400}$

So , Cost of Ploughing the garden is Rs.8400 ....