Math, asked by naveenanadiya, 6 months ago

A rectangular garden is 185 m long and 220 m wide. It has two roads in its centre of
uniform width of 4 m, one parallel to its length and the other parallel to its breadth.
Find the cost of levelling the roads at 1.25 per sq.m.​

Answers

Answered by abhinavbalamurugan
1

Answer:

This is the correct answer also u didnt say the price of levelling

Step-by-step explanation:

The cost of leveling the roads inside the rectangular garden at 12.50 per square metre is Rs.  20,050 .

Step-by-step explanation:

The dimension of the rectangular garden:

Length, l = 185 m

Breadth, b = 220 m

Two roads of width 4 m runs at the centre of the garden and are parallel to the sides of the rectangular garden.

Now,

Area of the path running parallel to the length of the garden = l × w = 185 × 4 = 740 m²

Area of the path running parallel to the breadth of the garden = b × w = 220 × 4 = 880 m²

Area of the common portion between the two cross roads = 4 × 4 = 16 m²

Therefore,  

The total area of the roads is given by,

= [Area of the path running parallel to the length] + [Area of the path running parallel to the breadth] – [Area of the common portion]

= 740 + 880 – 16

= 1604 m²

It is also given that the cost of levelling the two roads is Rs. 12.50 per meter square.

Thus,

The cost of levelling the 1604 m² of roads will be,

= Rs. 12.5 × 1604 m²

= Rs. 20050

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