a rectangular garden is 185m long and 220m wide. It has two roads in center of uniform width 4m, one parallel to its length and the other parallel to its breadth . Find the cost of leveling the road at 1.25 per sq. m
Answers
Step-by-step explanation:
Given :-
A rectangular garden is 185m long and 220m wide. It has two roads in center of uniform width 4m, one parallel to its length and the other parallel to its breadth .
To find :-
Find the cost of leveling the road at 1.25 per sq.m
Solution :-
Given that
The length of the rectangular garden (l) = 185 m
The breadth of the rectangular garden (b)=220 m
The width of the road (w) = 4 m
It has two roads in center of uniform width 4m, one parallel to its length and the other parallel to its breadth .
We know that
Area of a rectangle = lb sq.units
The area of the rectangle in which the road is parallel to the length of the rectangular garden
Length = 185 m , breadth = 4 m
=> 185×4 sq.m
=> 740 sq.m
And
The area of the rectangle in which the road is parallel to the breadth of the rectangular garden
Length = 220 m , breadth = 4 m
=> 220×4 sq.m
=> 880 sq.m
Area of the road which is common portion of the garden
Length = 4 m and breadth = 4 m
Area = 4×4 = 16 sq.m
Now ,
The total area of the road
= [Area of the road which is running parallel to the length+ Area of the road which is running parallel to the breadth] - Area of the road which is running common portion
= 740+880-16
=> 1620 - 16
=> 1604 sq.m
Total area of the road = 1604 sq.m
Now,
The cost of levelling the road per 1 sq.m = Rs. 1.25
The total cost of levelling the road of 1604 sq.m
at the rate of Rs. 1.25
=> 1604×1.25
=> Rs. 2005
Therefore, The cost = Rs. 2005
Answer:-
The total cost of the levelling the road is Rs. 2005
Used formulae:-
→ Area of a rectangle = lb sq.units
- l = length
- b = breadth
Step-by-step explanation: