A rectangular garden is 45 m long and 30m wide. A path of 1.5 m width is to be paved inside the garden along its boundary using tiles of 18 cm × 12 cm. How many such tiles will be required?
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Step-by-step explanation:
We have,
Length AB = 40 m and breadth BC = 25 m
∴ Area of lawn ABCD = 40 m x 25 m = 1000 m2
Length PQ = (40 + 2 + 2 ) m = 44 m
Breadth QR = ( 25 + 2 + 2 ) m = 29 m
∴ Area of PQRS = 44 m x 29 m = 1276 m2
Now,
Area of the path = Area of PQRS − Area of the lawn ABCD
= 1276 m2 − 1000 m2
= 276 m2
Rate of levelling the path = Rs. 8.25 per m2
∴ Cost of levelling the path = Rs. ( 8.25 x 276)
= Rs. 2277
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