Question

. A rectangular garden is 60 m long and 16 m broad. A path of uniform width of 2 m surrounds the garden inside it. Find the area of the path and the remaining area of the garden. Also, find the cost of paving the path with bricks at 20 per square metre. ​

Answer 1

Answer:

2(2×60)+2(12×2)

240+48

288m²

cost = 288×20

5760 rupees is required

Answer 2

${\tt{\underline{Given :-}}}$

There is a rectangular garden.

It has dimensions of 60 m × 16 m

There is a path of uniform width of 2 m that surrounds the garden inside it.

Cost of paving the path with bricks is 20 per m

${\tt{\underline{Need\;to\;find:-}}}$

Area of path

The Remaining are of garden

Cost

${\tt{\underline{Answer:-}}}$

(1) Total area

The Area of a rectangle is the product of length and breadth. It is written in the mathematical way as :-

$\tt Area=Length\times Breadth$

$\tt Area=60\times16$

$\tt Area=960\;m^2$

(2) Remaining area

$\tt Length=60-2$

$\tt Length=58\;m$

$\tt Breadth=16-2$

$\tt Breadth=14\;m$

$\tt Area=Length\times Breadth$

$\tt Area=58\times 14$

$\tt Area=812\;m^2$

(3) Cost of paving

$\tt Area\;of\;path=960-812$

$\tt Area\;of\;path=148\;m$

$\tt Cost=Area\times Rate$

$\tt Cost=148\times20$

$\tt Cost=2960$