A rectangular garden is 60 m long and 40 m wide. Through the middle of the garden run two straight path straight path at right angle to each other. If the width of each path is 2 m , find the area of the remaining portion of the garden.
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Answer:
Area of garden
60 \times 40 = 240060×40=2400
Area of first path
60 \times 2 = 12060×2=120
Area of second path
40 \times 2 = 8040×2=80
Add
120 + 80 = 200120+80=200
Area of middle section
2 \times 2 = 42×2=4
Area of rem
2400 - 196 = 22042400−196=2204
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