A rectangular garden is 60m long and 40m wide. Through the middle of the garden run two straight paths at right angles to each other. If the width of each path is 2m, find the area of the remaining portion of the garden.
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Area of the rectangle = Length×Breadth=65×50=3250m2Length×Breadth=65×50=3250m2
Given Width of the Path = 2m
Length of the Path is Parellel to the side , Hence Length = 65 m
Area of the Path 1 = Length×Width=65×2=130m2Length×Width=65×2=130m2
Given Breadth of the Path = 2m
Length of the Path2 is Parellel to the other side , Hence Length = 50 m
Area of the Path2 = Length×Breadth=50×2=100m2Length×Breadth=50×2=100m2
Add Both the Area of the Path = 130+100=230m2130+100=230m2
Area of the Common Field ABCD = 2×2=4m22×2=4m2
As both path are overlapping each other, so to calculate the area of shaded portion area of one square should be deducted from the area of the total path.
∴∴ Total Area for the Path Construction = 230−4=226m2230−4=226m2
∴∴ Cost of Constructing the Path = 230−4=226×69=15594
Given Width of the Path = 2m
Length of the Path is Parellel to the side , Hence Length = 65 m
Area of the Path 1 = Length×Width=65×2=130m2Length×Width=65×2=130m2
Given Breadth of the Path = 2m
Length of the Path2 is Parellel to the other side , Hence Length = 50 m
Area of the Path2 = Length×Breadth=50×2=100m2Length×Breadth=50×2=100m2
Add Both the Area of the Path = 130+100=230m2130+100=230m2
Area of the Common Field ABCD = 2×2=4m22×2=4m2
As both path are overlapping each other, so to calculate the area of shaded portion area of one square should be deducted from the area of the total path.
∴∴ Total Area for the Path Construction = 230−4=226m2230−4=226m2
∴∴ Cost of Constructing the Path = 230−4=226×69=15594
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Ankita,Hello! I am Mayuri.
Can you please send me the answers of ENGLISH-1--->Pg. No.-101=>Exercise-11 & 13???
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Here is the answer of it......
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