Math, asked by ajayenterpries210, 4 months ago

A rectangular garden with length 90 m and breadth 55 m has two crossroads. One
crossroad is 3.5 m wide and is parallel to the length and the other crossroad 3m
wide and is parallel to the breadth of the garden. Find the cost of constructing these
crossroads at 20 per m^.​

Answers

Answered by ranuyada9685
3

Answer:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

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