A rectangular ground 750m long and 450m broad has in the middle of it, roads 5m wide, running at right angles to each other. One road is along the breadth and one is along the length. Find the total area covered by the roads.
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given
length = 750m
breadth = 450m
width = 5m
TSA = 2 (lb+bh+hl)
= 2 ( 750×450+450×5+5×750)
= 2 (337500+2250+3750)
= 2 (343500)
= 687000 cm^2
length = 750m
breadth = 450m
width = 5m
TSA = 2 (lb+bh+hl)
= 2 ( 750×450+450×5+5×750)
= 2 (337500+2250+3750)
= 2 (343500)
= 687000 cm^2
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