A rectangular ground 80m long and 60m broad it has two cross roads of equal width one is parallel to length and the other parallel to breadth. If the area of these roads is 675 sq. M. Find the width of each road.
Answers
= 4125
55× 75 = 4125
breadth of road = 80-75
=5m
Concept:
The area of a rectangle in a two-dimensional plane is the area that it occupies. A quadrilateral, a form of two-dimensional object with four sides and four vertices, is what a rectangle is. The rectangle's four angles are all right angles or exactly 90 degrees. The rectangle's opposing sides are equal and parallel to one another. It should be noted that a parallelogram likewise has equal and parallel opposite sides, but the angles are not exactly 90 degrees.
Area of rectangle= length x breadth
Perimeter of rectangle=2(length +breadth)
Given:
A rectangular ground 80m long and 60m broad it has two cross roads of equal width one is parallel to length and the other parallel to breadth. If the area of these roads is 675 sq. m
Find:
Find the width of the road.
Solution:
Length of the ground=80m
Breadth of the ground =60m
Area of rectangular ground =80 x 60 m
= 4800m
Area of cross road =675 m
Area of the ground unpaved=4800- 675
= 4125
But,
55× 75 = 4125
So,breadth of road = 80-75
=5m
Therefore, the breadth of the road is =5m
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